Measures of Shape
Unit III Ā· Lecture 22
š¤ What is Kurtosis?
š Formal Definition
Kurtosis is a statistical measure that describes the shape of a distribution's tails relative to its overall shape. Specifically, it measures whether data is concentrated in the tails (heavy-tailed) or concentrated near the centre (light-tailed) compared to a normal distribution.
š” Analogy: Hats on a Hat Rack
Think of different distributions as different types of hats sitting on a hat rack:
Leptokurtic (high kurtosis) = Top hat ā tall, narrow peak with long brims (heavy tails). Most data is either very close to the centre or very far away.
Mesokurtic (normal kurtosis) = Baseball cap ā moderate peak, moderate brim. The "standard" shape.
Platykurtic (low kurtosis) = Beret ā flat, spread out. Data is evenly distributed with no strong concentration at the centre or tails.
š¬ Common Misconception: Kurtosis is often described as measuring "peakedness." While partially true, it more accurately measures tail heaviness ā how much data resides in the tails versus the shoulders of the distribution. A distribution can have a sharp peak but light tails (low kurtosis) or a moderate peak but very heavy tails (high kurtosis).
Measures of Shape
Unit III Ā· Lecture 22
āļø Example 1: Computing Kurtosis from Moments
š Problem
For a distribution, the central moments are: μā = 20, μā = 2500. Find βā, γā, and interpret.
š Solution
Given: μā = 20, μā = 2500
βā = μā / μā²
βā = 2500 / (20)² = 2500 / 400 = 6.25
γā = βā ā 3
γā = 6.25 ā 3 = +3.25
Result & Interpretation
βā = 6.25 | γā = +3.25
Leptokurtic
The distribution is leptokurtic (heavy-tailed). βā = 6.25 is significantly above 3, indicating a sharper peak and heavier tails than a normal distribution. There is a higher probability of extreme values (outliers) compared to a normal distribution with the same variance.
Measures of Shape
Unit III Ā· Lecture 22
āļø Example 2: Kurtosis from Raw Moments
š Problem
The raw moments about the origin are: μā' = 4, μā' = 20, μā' = 100, μā' = 600. Find the kurtosis of the distribution.
š Solution ā Step 1: Central Moments
μā = μā' ā (μā')² = 20 ā 16 = 4
μā = μā' ā 3μā'μā' + 2(μā')³ = 100 ā 3(20)(4) + 2(64) = 100 ā 240 + 128 = ā12
μā = μā' ā 4μā'μā' + 6μā'(μā')² ā 3(μā')ā“
= 600 ā 4(100)(4) + 6(20)(16) ā 3(256)
= 600 ā 1600 + 1920 ā 768 = 152
š Solution ā Step 2: Kurtosis
βā = μā / μā² = 152 / 16 = 9.5
γā = 9.5 ā 3 = +6.5
Bonus ā Skewness:
γā = μā / μā^(3/2) = ā12 / 8 = ā1.5 (left-skewed)
Results
βā = 9.5 | γā = +6.5 | γā = ā1.5
The distribution is highly leptokurtic (very heavy tails) and strongly left-skewed. This suggests data with extreme low values and a sharp concentration near the centre-right.
Measures of Shape
Unit III Ā· Lecture 22
āļø Example 3: Kurtosis of Frequency Distribution
š Problem
Find the kurtosis for the following data:
š Solution
N = 30, Ī£fįµ¢xįµ¢ = 180, xĢ = 6
Σfᵢxᵢ² = 1200, Σfᵢxᵢ³ = 8640, Σfᵢxᵢⓠ= 66240
μā' = 1200/30 = 40, μā' = 8640/30 = 288, μā' = 66240/30 = 2208
μā = 40 ā 36 = 4
μā = 288 ā 3(40)(6) + 2(216) = 288 ā 720 + 432 = 0 (symmetric!)
μā = 2208 ā 4(288)(6) + 6(40)(36) ā 3(1296) = 2208 ā 6912 + 8640 ā 3888 = 48
βā = 48 / 16 = 3.0
γā = 3.0 ā 3 = 0.0
Result
βā = 3.0 | γā = 0.0 | γā = 0.0
Mesokurtic & Symmetric
The distribution is mesokurtic (normal-like kurtosis) and perfectly symmetric. The symmetric frequencies (3, 7, 10, 7, 3) produce a shape very close to a normal distribution.
Measures of Shape
Unit III Ā· Lecture 22
š Percentile-Based Measure of Kurtosis
š Definition
An alternative, robust measure of kurtosis uses percentiles (specifically quartiles and percentiles) instead of moments. This avoids the heavy influence of extreme outliers on μā.
š Percentile Kurtosis Formula (Moors' Method)
A common percentile-based kurtosis measure is:
K_perc = (Pāā
ā Pāā
) / (Pāā ā Pāā)
This ratio compares the interquartile range (middle 50%) to the inter-decile range (middle 80%).
Interpretation:
⢠Higher K_perc ā more data in the middle relative to tails ā leptokurtic
⢠Lower K_perc ā data more evenly spread ā platykurtic
⢠For a normal distribution, K_perc ā 0.26
š” Advantage: Percentile-based kurtosis is resistant to outliers because it does not involve raising deviations to the fourth power. It is preferred when data contains extreme values that would distort moment-based measures.
Measures of Shape
Unit III Ā· Lecture 22
āļø Kurtosis vs Skewness ā What Each Tells You
| Feature | Skewness (γā) | Kurtosis (βā / γā) |
| What it measures | Asymmetry (direction of lean) | Tail heaviness / peakedness |
| Based on | Third central moment (μā) | Fourth central moment (μā) |
| Normal distribution | γā = 0 (symmetric) | βā = 3, γā = 0 (mesokurtic) |
| Key question | "Which tail is longer?" | "How heavy are the tails?" |
| Sign matters? | Yes (positive or negative) | βā is always positive; γā can be negative |
| Independence | A distribution can be symmetric but have any kurtosis | A distribution can have any skewness but normal kurtosis |
| Together they tell you | Skewness + Kurtosis give a near-complete picture of a distribution's shape beyond its mean and variance. |
š” Key Insight: Skewness and kurtosis are independent characteristics. A distribution can be symmetric with heavy tails (e.g., Student's t), or skewed with normal-like tails. You need both to fully describe the shape of a distribution.
Measures of Shape
Unit III Ā· Lecture 22
āļø Example 4: Comparing Kurtosis of Two Datasets
š Problem
Two datasets have the following central moments. Compare their shapes.
š Dataset A
μā = 10, μā = 0, μā = 300
βā = 300/100 = 3.0
γā = 3.0 ā 3 = 0.0
γā = 0/⦠= 0
ā Mesokurtic, Symmetric
š Dataset B
μā = 10, μā = 0, μā = 800
βā = 800/100 = 8.0
γā = 8.0 ā 3 = +5.0
γā = 0/⦠= 0
ā Highly Leptokurtic, Symmetric
Comparison
Both datasets have the same variance (μā = 10) and are symmetric (γā = 0).
But Dataset B has much heavier tails (βā = 8 vs 3).
Dataset B has more extreme values (far from the mean) despite having the same spread (variance). This is the additional information that kurtosis provides beyond variance.
Measures of Shape
Unit III Ā· Lecture 22
š§ Quick Quiz ā Lecture 22
Q1: A distribution with βā = 5 is classified as:
A) Leptokurtic
B) Mesokurtic
C) Platykurtic
D) Symmetric
Q2: The excess kurtosis (γā) of a normal distribution is:
Q3: Kurtosis primarily measures:
A) The centre of the distribution
B) The asymmetry of the distribution
C) The heaviness of tails relative to a normal distribution
D) The spread of the distribution
Q4: If μā = 9 and μā = 1458, then βā equals:
Q5: A uniform distribution is:
A) Leptokurtic
B) Mesokurtic
C) Platykurtic
D) Highly skewed
Q6: If every value in a dataset is multiplied by 4, the kurtosis (βā) will:
A) Increase 4 times
B) Increase 16 times
C) Remain the same
D) Decrease to 1/4th
Q7: Which of the following is true about kurtosis and skewness?
A) They always have the same sign
B) High kurtosis implies high skewness
C) They are independent ā a distribution can have any combination of skewness and kurtosis
D) Kurtosis can only be computed if skewness is known
Q8: In finance, leptokurtic returns imply:
A) Returns are always positive
B) Extreme gains and losses occur more frequently than a normal model predicts
C) The distribution is symmetric
D) Risk is lower than expected
Measures of Shape
Unit III Ā· Lecture 22
š Homework & Practice
š Practice Tasks
1. Given μā = 25 and μā = 5000, find βā and γā. Classify the distribution.
2. The raw moments of a distribution are: μā' = 6, μā' = 45, μā' = 360, μā' = 3200. Find the central moments and compute βā, γā, and γā. Describe the shape completely.
3. For a frequency distribution with xįµ¢ = 1, 2, 3, 4, 5 and fįµ¢ = 2, 5, 8, 5, 2, compute the kurtosis. Is it mesokurtic?
4. Explain why a distribution can have βā > 3 but γā = 0. Give a real-world example.
5. Compare the kurtosis of a normal distribution (βā = 3) with a Student's t-distribution with 4 degrees of freedom (βā = 9). What does this mean for risk assessment?
6. If the kurtosis of a grouped dataset (class width c = 10) is computed as βā = 4.5 before Sheppard's correction, and the uncorrected moments are μā = 50 and μā = 11250, find the corrected kurtosis.
7. A dataset has βā = 1.8. What type of distribution is this? Name a theoretical distribution that has approximately this kurtosis.
8. BONUS: Prove that the kurtosis of a Bernoulli distribution with parameter p is: βā = (1 ā 3p(1āp)) / (p(1āp)). Evaluate this for p = 0.5 and verify that βā = 1 (the minimum possible kurtosis).
š” Tip: Remember the three benchmarks: βā = 1.8 (uniform/platykurtic), βā = 3 (normal/mesokurtic), βā > 3 (leptokurtic). These three reference points will help you quickly classify any distribution.
Measures of Shape
Unit III Ā· Lecture 22
Thank You!
Questions? Let's discuss!
Upcoming in Unit III
Lecture 23: Lorenz Curve & Measures of Inequality
Lecture 24: Unit III Review & Problem-Solving Session
Unit IV: Correlation & Regression Analysis
Unit III Ā· Lecture 22 Ā· BDS113 Introduction to Statistics Ā· B.Sc. Data Science, Semester II